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sql 去重查询的方法:重复记录根据单个字段 peopleId 来判断,使用语句删除,代码为【where peopleId in (select peopleId from people group by peopleId】。
sql 去重查询的方法:
sql 单表 / 多表查询去除重复记录
单表 distinct
多表 group by
group by 必须放在 order by 和 limit 之前,不然会报错
1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
select * from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) 1)
2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有 rowid 最小的记录
delete from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) 1)
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId) 1)
3、查找表中多余的重复记录(多个字段)
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) 1)
4、删除表中多余的重复记录(多个字段),只留有 rowid 最小的记录
delete from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*) 1)
5、查找表中多余的重复记录(多个字段),不包含 rowid 最小的记录
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*) 1)
(二)
比方说
在 A 表中存在一个字段“name”,
而且不同记录之间的“name”值有可能会相同,
现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
Select Name,Count(*) From A Group By Name Having Count(*) 1
如果还查性别也相同大则如下:
Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) 1
(三)
方法一
declare @max integer,@id integer
declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*);1
open cur_rows
fetch cur_rows into @id,@max
while @@fetch_status=0
begin
select @max = @max -1
set rowcount @max
delete from 表名 where 主字段 = @id
fetch cur_rows into @id,@max
close cur_rows
set rowcount 0
方法二
"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如 Name 字段重复,而其他字段不一定重复或都重复可以忽略。
1、对于第一种重复,比较容易解决,使用
select distinct * from tableName
就可以得到无重复记录的结果集。
如果该表需要删除重复的记录(重复记录保留 1 条),可以按以下方法删除
select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp
发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。
2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下
假设有重复的字段为 Name,Address,要求得到这两个字段唯一的结果集
select identity(int,1,1) as autoID, * into #Tmp from tableName
select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
select * from #Tmp where autoID in(select autoID from #tmp2)
最后一个 select 即得到了 Name,Address 不重复的结果集(但多了一个 autoID 字段,实际写时可以写在 select 子句中省去此列)
(四)
查询重复
select * from tablename where id in (select id from tablename
group by id
having count(id) 1
)
3、查找表中多余的重复记录(多个字段)
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) 1)
运行会产生问题,where(a.peopleId,a.seq) 这样的写发是通不过的!!!
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